![]() ![]() We use the info obtained for the point A to calculate the total time of flight t tot. (For simplicity we take the magnitude of gravitational acceleration equal to 10 m/s 2.) Yet, the maximum horizontal displacement is Δx max = 4m as the object falls on the ground at that horizontal position.īefore starting with the solution, let's complete the figure with the data obtained above. The corresponding horizontal coordinate is xA = 2m. This means x 0 = 0 and y 0 = 0.Īlso, it is obvious the object reaches its maximum position at yA = y max = 4m. Thus, we see that the initial position of the object is at (0, 0). We can obtain some useful information from the figure.
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